2x^2+x-1/8=0

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Solution for 2x^2+x-1/8=0 equation: 


x in (-oo:+oo)

2*x^2+x-(1/8) = 0

2*x^2+x-1/8 = 0

2*x^2+x-1/8 = 0

DELTA = 1^2-(-1/8*2*4)

DELTA = 2

DELTA > 0

x = (2^(1/2)-1)/(2*2) or x = (-2^(1/2)-1)/(2*2)

x = (2^(1/2)-1)/4 or x = (-(2^(1/2)+1))/4

x in { (-(2^(1/2)+1))/4, (2^(1/2)-1)/4 }

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